Skip to main content

TCS Aptitude test, Placement Questions with Solution



1) If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319 ?
Sol: log 0.317=0.3332 and log 0.318=0.3364, then
log 0.319=log0.318+(log0.318-log0.317) = 0.3396

2) A box of 150 packets consists of 1kg packets and 2kg packets. Total weight of box is 264kg. How many 2kg packets are there ?
Sol: x= 2 kg Packs
y= 1 kg packs
x + y = 150     .......... Eqn 1
2x + y = 264   .......... Eqn 2
Solve the Simultaneous equation; x = 114
so, y = 36
ANS :  Number of 2 kg Packs = 114.

3) My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed?

Options: a)6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00
Sol: The destination place is 80 degree west to the starting place. Hence the time difference between these two places is 5 hour 20 min. (=24hr*80/360).
When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours).
Hence, the time at the destination place is 12 noon - 5:20 hours = 6: 40 AM

4) A plane moves from 9°N40°E to 9°N40°W. If the plane starts at 10 am and takes 8 hours to reach the destination, find the local arrival time ?
Sol: Since it is moving from east to west longitide we need to add both
ie,40+40=80
multiply the ans by 4
=>80*4=320min
convert this min to hours ie, 5hrs 33min
It takes 8hrs totally . So 8-5hr 30 min=2hr 30min
So the ans is 10am+2hr 30 min
=>ans is 12:30 it will reach

5) The size of the bucket is N kb. The bucket fills at the rate of 0.1 kb per millisecond. A programmer sends a program to receiver. There it waits for 10 milliseconds. And response will be back to programmer in 20 milliseconds. How much time the program takes to get a response back to the programmer, after it is sent? answer with explanation.
Sol: see it doesn't matter that wat the time is being taken to fill the bucket.after reaching program it waits there for 10ms and back to the programmer in 20 ms.then total time to get the response is 20ms +10 ms=30ms...it's so simple....

6) A fisherman's day is rated as good if he catches 9 fishes, fair if 7 fishes and bad if 5 fishes. He catches 53 fishes in a week n had all good, fair n bad days in the week. So how many good, fair n bad days did the fisher man had in the week
Ans: 4 good, 1 fair n 2 bad days
Sol: Go to river catch fish
4*9=36
7*1=7
2*5=10
36+7+10=53...
take what is given 53
good days means --- 9 fishes so 53/9=4(remainder=17)  if u assume 5 then there is no chance for bad days.
fair days means ----- 7 fishes so remaining 17 --- 17/7=1(remainder=10) if u assume 2 then there is no chance for bad days.
bad days means -------5 fishes so remaining 10---10/5=2days.
  Ans: 4 good, 1 fair, 2bad. ==== total 7 days.

x+y+z=7--------- eq1
9*x+7*y+5*z=53 -------eq2
multiply eq 1 by 9,
9*x+9*y+9*z=35 -------------eq3
from eq2 and eq3
2*y+4*z=10-----eq4
since all x,y and z are integer i sud put a integer value of y such that z sud be integer in eq 4 .....and ther will be two value y=1 or 3 then z = 2 or 1 from eq 4

for first  y=1,z=2 then from eq1 x= 4
so 9*4+1*7+2*5=53.... satisfied
now for second y=3 z=1 then from eq1 x=3
so 9*3+3*7+1*5=53 ......satisfied
so finally there are two solution of this question
(x,y,z)=(4,1,2) and (3,3,1)...

7) Y catches 5 times more fishes than X. If total number of fishes caught by X and Y is 42, then number of fishes caught by X?
Sol: Let no. of fish x catches=p
no. caught by y =r
r=5p.
r+p=42
then p=7,r=35

8) Three companies are working independently and receiving the savings 20%, 30%, 40%. If the companies work combinely, what will be their net savings?
Sol: suppose total income is 100
so amount x is getting is 80
y is 70
z =60
total=210

but total money is 300
300-210=90
so they are getting 90 rs less
90 is 30% of 300 so they r getting 30% discount

9) The ratio of incomes of C and D is 3:4.the ratio of their expenditures is 4:5. Find the ratio of their savings if the savings of C is one fourths of his income?
Sol: incomes:3:4
expenditures:4:5
3x-4y=1/4(3x)
12x-16y=3x
9x=16y
y=9x/16
(3x-4(9x/16))/((4x-5(9x/16)))
ans:12/19


10) If G(0) = -1 G(1)= 1 and G(N)=G(N-1) - G(N-2) then what is the value of G(6)?
Ans: -1
bcoz g(2)=g(1)-g(0)=1+1=2
g(3)=1
g(4)=-1
g(5)=-2
g(6)=-1

Comments

Popular posts from this blog

Cognizant Company Profile and it's information for Interview

Website: www.cognizant.com HQ Teaneck, NJ Industry Information Technology Services Size 130K+ Employees, $6B+ Revenue NASDAQ CTSH Competitors Infosys, Wipro, Tata Consultancy Services   About cognizant Cognizant Corporate view: Cognizant is an American multinational IT services and consulting corporation headquartered in Teaneck, New Jersey, United States. Cognizant has been named to the 2010 Fortune 100 Fastest-Growing Companies List for the eighth consecutive year. Cognizant has also been named to the Fortune 1000 and Forbes Global 2000 lists. It has consistently ranked among the fastest growing companies including the 2010 Business Week 50 list of the top-performing U.S. companies, the Business Week Hottest Tech Companies 2010, and the Forbes Fast Tech 2010 list of 25 Fastest Growing Technology Companies In America. Founded: 1994 Headquarters: Teaneck, New Jersey, U.S. Key people:  Francisco D'Souza (President & CEO) Lakshmi Naray...

CIVIL SERVICES' (I.A.S.) EXAMINATION

The Union Public Service Commission (U.P.S.C.)  conducts Civil Services' Examination once a year in two stages. The Preliminary Examination (Objective Type) for selection of candidates for the Main Examination is held in the month of May. The Civil Services Main Examination  is held in the months of October/November. Blank application forms and other particulars are published in the Employment News, generally in the month of December. The last date for the submission of applications to the Secretary, Union Public Service Commission, Dholpur House, Shahjahan Road, NewDelhi-11001 1 is usually the last week of January of the year of examination. The Combined Civil Services Examination is conducted for Recruitment to the following Services/Posts: 1. Indian Administrative Service. 2. Indian Foreign Service. 3. Indian Police Service. 4. Indian P & T Accounts & Finance Service, Group 'A'. 5. Indian Audit and Accounts Service, Group 'A'. 6. Indian Customs and Centr...

Infosys delays 17,000 campus recruitment offers

Bangalore: With a challenging environment, and low visibility into client spend, Infosys has said that it will be deferring joining dates, and the management is also putting some cost saving measures in place, reports Shreya Roy of CNBC-TV18. Infy had decided that with its current business needs in mind it will defer its campus recruitment process. The company had initially made 27,000 campus offers, but now the company says that 17,000 of these will be deferred by up to three months. However, the firm has reiterated that it plans to honour each of these offers in due course of time. In fact the company which prided itself on a six-month long extensive training programme for fresh intakes has also decided to cut the period short by two months, four months of this training programme will be conducted at its sprawling Mysore campus, while two months will be an online programme. With a challenging environment, and low visibility into client spend, Infy said it will delay...