Question 1 A train starts from station P towards Q with certain speed. Due to a problem, after crossing 50km, the train slows down to 2/3 rd of its actual speed and it reaches Q 50 minutes later than the planned time. Suppose the technical problem had happened after crossing 60 km and the train would had reached 40 minutes late. What is the actual(original) speed of the train and what is the distance between P and Q ? a)30km/hr, 100km b)20km/hr,80km c)40km/hr,150km d)50km/hr,150km Answer : a)30km/hr, 100km Solution: Let the distance between P and Q be X and the speed initially be V. Note that the train travels 50km with speed V and the remaining distance(X-50)km with speed 2/3 of V. According to the above condition, with the formula " distance/speed = time", we can have Time Taken For First 50 Km + Time Taken For Remaining (X-50) Km = Planned Time + Extra Time Due To Problem [50/V]+[(X-50)/(2V/3)] = [X/V]+5/6 (here 50 minutes = 5/6 hours) [100+3X-1...
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